Find the median for the following frequency distribution table:

Class Intervals

110 - 119

120 - 129

130 - 139

140 - 149

150 - 159

160 - 169

Frequency

6

8

15

10

6

5

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Solution

We first draw the cumulative frequency table for the given data as:

Now, we have N = 50.

Thus, (130−139) is the median class.

We also have .

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Similar questions

Q. Find the median for the following frequency distribution table:

Class Intervals	$110 - 119$	$120 - 129$	$130 - 139$	$140 - 149$	$150 - 159$	$160 - 169$
Frequency	$6$	$8$	$15$	$10$	$6$	$5$

Find the median for the following frequency distribution table:

Class-intervals	0 - 5	5 -10	10 - 15	15 - 20	20 - 25	25 - 30
Frequency	5	3	9	10	8	5

Find the median of the following data.

$\begin{matrix} C l a s s i n t e r v a l & 100 - 110 & 110 - 120 & 120 - 130 & 130 - 140 & 140 - 150 F r e q u e n c y & 6 & 9 & 14 & 2 & 19 \end{matrix}$

Q. Calculate mode of the following series:

Class Interval	30−59	60−89	90−119	120−149	150−179	180−209	210−239
Frequency	4	7	12	15	18	6	5

Find the mean, using assumed-mean method:

$\begin{matrix} Class & 100 - 120 & 120 - 140 & 140 - 160 & 160 - 180 & 180 - 200 Frequency & 10 & 20 & 30 & 15 & 5 \end{matrix}$

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Class Intervals	110 - 119	120 - 129	130 - 139	140 - 149	150 - 159	160 - 169
Frequency	6	8	15	10	6	5

Find the median for the following frequency distribution table: Class Intervals 110 - 119 120 - 129 130 - 139 140 - 149 150 - 159 160 - 169 Frequency 6 8 15 10 6 5

We first draw the cumulative frequency table for the given data as: Now, we have N = 50. Thus, (130−139) is the median class. We also have .

Find the median for the following frequency distribution table:

Class Intervals

110 - 119

120 - 129

130 - 139

140 - 149

150 - 159

160 - 169

Frequency

6

8

15

10

6

5

We first draw the cumulative frequency table for the given data as:

Now, we have N = 50.

Thus, (130−139) is the median class.

We also have .