Question

Find the median for the following frequency distribution table:

Class Intervals	$110-119$	$120-129$	$130-139$	$140-149$	$150-159$	$160-169$
Frequency	$6$	$8$	$15$	$10$	$6$	$5$

Answer 1

$Ci$	110-119	120-129	130-139	140-149	150-159	160-169
$f$	6	8	15	10	6	5
$cf$	6	14(m)	29	39	45	50

$\frac{N}{2}=\frac{50}{2}=25$ lies between $cf=14$ and $cf=29$

so, $130-139$ is Median class and $m=14$

Median $=l+\left(\frac{\left(N/2\right)-m}{f}\right)\times h$

$=130+\left(\frac{25-14}{15}\right)\times 9$

Median $=136.59$