CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Find the median from the following data: Class156101115162021252630313536404145Frequency710163224161152

Open in App
Solution

Sol:

The given series is of inclusive form. Converting it into exclusive form and preparing the cumulative frequency table, we get

Marks Frequency fi C.F
0.5-5.5 7 7
5.5-10.5 10 17
10.5-15.5 16 33
15.5-20.5 32 65
20.5-25.5 24 89
25.5-30.5 16 105
30.5-35.5 11 116
35.5-40.5 5 121
40.5-45.5 2 123
N=∑fi=123

N =123

=> N/2 = 61.5

Now,

The cumulative frequency just greater than 61.5 is 65 and corresponding class is 15.5-20.5.

Thus, the median class is 15.5-20.5

I = 15.5, h = 5, f = 32, c = C.F. preceding median class = 33 and N/2 = 61.5

Median = I+[h×(N/2−c)/f]=15.5+[5×(61.5−33)/32]

= 15.5+4.45 = 19.95

Hence, median = 19.95


flag
Suggest Corrections
thumbs-up
39
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Median
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon