Find the median of:
32, 37, 43, 49, 52, 54, 66, 67, 72, 78

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
53

Given data is already in ascending order
32, 37, 43, 49, 52, 54, 66, 67, 72, 78
Number of terms = 10 (even number of terms)
$M e d i a n = Average of the 5^{t h} a n d 6^{t h} t e r m$ .
= $\frac{5^{t h} t e r m + 6^{t h} t e r m}{2}$
= $\frac{52 + 54}{2} = 53$
Thus, median of the given data is 53.

Suggest Corrections

Similar questions

40

100

75, 65, 57, 50, 32, 54, 75, 67, 75, 88, 80, 42, 40, 41, 34, 78, 43, 61, 42, 46

68, 52, 43, 49, 59, 49, 67, 34, 33, 87, 97, 47, 46, 54, 48, 45, 51, 47, 41, 43

10

(30 - 39), (40 - 49), . . .

30 - 39

Given below are the marks (out of 100) in mathematics obtained by 40 students of 6^th standard in an annual examination.

Which section has the best way of arranging the students according to their marks?

Given below are the marks (out of 100) in mathematics obtained by 40 students of Class VI in an annual examination.

Which section has arranged their marks in ascending order?

30

k g

43, 45, 64, 42, 54, 78, 91, 90, 56, 37, 48, 90, 50, 48, 67

85, 30, 39, 49, 40, 50, 45, 68, 90, 50, 34, 56, 88, 43, 50

Join BYJU'S Learning Program