Question

Find the median of each of the following data:
$\left(i\right)$ $7$, $10$, $5$, $20$, $18$, $25$, $17$
$\left(ii\right)$ $3$, $5$, $9$, $2$, $8$, $7$, $6$, $7$, $4$
$\left(iii\right)$ $37$, $42$, $31$, $46$, $25$, $27$, $30$, $32$, $41$

• A. $\left(i\right)$ $18$
  $\left(ii\right)$ $4$
  $\left(iii\right)$ $20$
• B. $\left(i\right)$ $5$
  $\left(ii\right)$ $36$
  $\left(iii\right)$ $13$
• C. $\left(i\right)$ $17$
  $\left(ii\right)$ $6$
  $\left(iii\right)$ $32$
• D. $\left(i\right)$ $9$
  $\left(ii\right)$ $29$
  $\left(iii\right)$ $30$

Answer 1

The correct option is C $\left(i\right)$ $17$

$\left(ii\right)$ $6$
$\left(iii\right)$ $32$
$\left(i\right)$ By arranging the given no's in increasing order, we get:
$5,7,10,17,18,20,25$
Total terms $=7$
since, the middle most term is $4^{th}$.
$\therefore$ value of median is $17$
$\left(ii\right)$ By arranging the given no's in increasing order, we get:
$2,3,4,5,6,7,7,8,9$
Total terms $=9$
since, the middle most term is $5^{th}$.
$\therefore$ value of median is $6$
$\left(iii\right)$ By arranging the given no's in increasing order, we get:
$25,27,30,31,32,37,41,42,46$
Total terms $=9$
since, the middle most term is $5^{th}$.
$\therefore$ value of median is $32$