Find the median of the following cumulative frequency distribution:
xfrequencyCumulative frequency221134233925458135482156930684347843884240
54
Here, the sum of frequencies, n = 40, which is even.
So, the median terms will be the n2th and the (n2+1)th observations, i.e. the 20th and the 21st observations.
Both the 20th and the 21st observations are 54.
So, the median term will be 54.