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B
110
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C
55
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D
100
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Solution
The correct option is C 55 ClassIntervalFrequencyCumulativeFrequency0−205520−40111640−60122860−80134180−100950
In the above distribution the total number of observations is 50. ∴N=50⟹N2=25. The cumulative frequency that is greater than 25 but closest to 25 is 28. The class corresponding to this frequency is 40-60. This is the median class.
Median = LRL+(N2−fcfm)×i, where LRL stands for the lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval ⟹Median=40+25−1620×20=55