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Question

Find the median of the following data.

Class interval02020404060608080100Frequency51112139


A
50
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B
110
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C
55
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D
100
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Solution

The correct option is C 55
Class IntervalFrequencyCumulative Frequency0205520401116406012286080134180100950

In the above distribution the total number of observations is 50.
N=50N2=25.
The cumulative frequency that is greater than 25 but closest to 25 is 28. The class corresponding to this frequency is 40-60. This is the median class.

Median = LRL+(N2fcfm)×i,
where LRL stands for the lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval
Median=40+251620×20=55


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