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Question

Find the median of the following data.

Class interval0−1010−2020−3030−4040−50Frequency1098176


A
20
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B
50
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C
54
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D
27.5
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Solution

The correct option is D 27.5
Class interval0101020203030404050Frequency1098176Cumulativefrequency1019274450

In the above distribution the total number of observations is 50.
N=50N2=25.
The cumulative frequency that is greater than 25 but closest to 25 is 27. The class corresponding to this frequency is 20-30. This is the median class.

Median=LRL+(N2fcfm)×i,
where LRL stands for the lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval
Median=20+25198×10=27.5

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