Find the median of the following data:Class interval25−3535−4545−5555−6565−7575−8585−95Frequency1216171581913
Class IntervalFrequencyCumulativeFrequency25−35121235−45162845−55174555−65156065−7586875−85198785−9513100
In the above distribution the total number of observations is 100.
Hence, n = 100.
n2=50.
The cumulative frequency that is greater than 50 but closest to 50 is 60. The class corresponding to this frequency is 55 - 65. This is the median class.
Median =l+(n2−cff)×h
where,
l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.
∴Median=55+50−4515×10=58.33