CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the median of the following data:Class interval25−3535−4545−5555−6565−7575−8585−95Frequency1216171581913


A
58.33
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
54.3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
32.33
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
51.67
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 58.33

Class IntervalFrequencyCumulativeFrequency25351212354516284555174555651560657586875851987859513100

In the above distribution the total number of observations is 100.
Hence, n = 100.

n2=50.

The cumulative frequency that is greater than 50 but closest to 50 is 60. The class corresponding to this frequency is 55 - 65. This is the median class.

Median =l+(n2cff)×h
where,
l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.

Median=55+504515×10=58.33


flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Measure of Central Tendency
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon