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Question

Find the median of the following data:Class interval25−3535−4545−5555−6565−7575−8585−95Frequency1216171581913


A
58.33
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B
54.3
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C
32.33
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D
51.67
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Solution

The correct option is A 58.33

Class IntervalFrequencyCumulativeFrequency25351212354516284555174555651560657586875851987859513100

In the above distribution the total number of observations is 100.
Hence, n = 100.

n2=50.

The cumulative frequency that is greater than 50 but closest to 50 is 60. The class corresponding to this frequency is 55 - 65. This is the median class.

Median =l+(n2cff)×h
where,
l is lower class limit of median class.
n is total number of observations.
cf is the cumulative frequency of the class preceding the median class.
f is the frequency of the median class and h is the class size.

Median=55+504515×10=58.33


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