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Question

Find the median of the following data.

No. of PlantsNo. of house02124346268481051012312142

A
8
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B
16
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C
48
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D
24
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Solution

The correct option is A 8
Class IntervalNumber of housesCumulative Frequency0211243446266841081051510123181214220

Median=LRL+(N2fcfm)×i,
where LRL = lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval

Median=8+10105×10

=8

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