The correct option is A 8
Class IntervalNumber of housesCumulative Frequency0−2112−4344−6266−84108−1051510−1231812−14220
Median=LRL+(N2−fcfm)×i,
where LRL = lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval
⟹Median=8+10−105×10
=8