Finding Median for Grouped Data When Class Intervals Are Given
Find the medi...
Question
Find the median of the following frequency distribution
Class
4−8
8−12
12−16
16−20
20−24
24−28
Frequency
9
16
12
7
15
1
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Solution
Class
Frequency
Cumulative frequency(c.f.)
4−8
9
9
8−12
16
9+16=25
12−16
12
25+12=37
16−20
7
37+7=44
20−24
15
44+15=59
24−28
1
59+1=60
Here n=60⇒n2=30 Cumulative frequency greater than 30 is 37 and the class corresponding to it is 12−16 ∴ Class 12−16 is the median class ∴ Lower limit(l)=12,n2=30,c.f.=25,f=12 and h=4 Subtituting the values, we get M=l+(n2−c.f.)f×h M=12+30−2512×4=12+53 =12+1.67 =13.67