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Question

Find the median of the following frequency distribution
Class48 812 1216 1620 2024 2428
Frequency916127151

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Solution

ClassFrequency Cumulative frequency(c.f.)
489 9
812 16 9+16=25
121612 25+12=37
16207 37+7=44
202415 44+15=59
24281 59+1=60
Here n=60 n2=30
Cumulative frequency greater than 30 is 37 and the class corresponding to it is 1216
Class 1216 is the median class
Lower limit(l)=12,n2=30,c.f.=25,f=12 and h=4
Subtituting the values, we get
M=l+(n2c.f.)f×h
M=12+302512×4=12+53
=12+1.67
=13.67
Hence, Median is 13.67

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