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Question

Find the median of the given data:

Wages(in Rs.)200−300300−400400−500500−600600−700No.of Labourers3520106

A
300
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B
420
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C
400
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D
470
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Solution

The correct option is D 470
Less than frequency distribution for the data is :
Wages less than Rs.Number of Labourers30034008500286003870044

WagesFrequencyCumulative frequency200300333004005840050020285006001038600700644

In the above distribution the total number of observations (labourers) is 44.
N=44N2=22.
The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median=LRL+(N2fcfm)×i,
where LRL stands for the lower real limit, fm=frequency of median class, fc=cumulative frequency above the median class and i=size of the class interval
For the given class,
LRL = 400, N=44, fc=8, fm=20 and i=100
Median=400+[22820]×100
=400+(228)×5=400+70=470
Therefore, the median is 470.

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