Find the median of the given data.
Wages (in Rs.)200−300300−400400−500500−600600−700No. of Labourers3520106
The correct option is C. 470
Less than frequency distribution for the data is :
WagesFrequencyCumulative frequency200−30033300−40058400−5002028500−6001038600−700644
In the above distribution the total number of observations (labourers) is 44. Hence n = 44.
n2=22.
The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median=l+(n2−cff)×h
Where,
l = lower limit of median class,
n = number of observations,
cf = cumulative frequency of class preceding the median class,
f = frequency of median class,
h = class size (assuming class size to be equal)
For the given class,
l=400
n=44
cf=8
f=20
h=100
Median=400+[22−820]×100
=400+(22–8)×5
=400+70
=470
∴ The median is 470.