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Question

Find the median of the given data.

Wages (in Rs.)200−300300−400400−500500−600600−700No. of Labourers3520106


A
300
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B
420
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C
400
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D
470
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Solution

The correct option is C. 470

Less than frequency distribution for the data is :

WagesFrequencyCumulative frequency200300333004005840050020285006001038600700644

In the above distribution the total number of observations (labourers) is 44. Hence n = 44.
n2=22.
The cumulative frequency that is greater than 22 but closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median=l+(n2cff)×h
Where,
l = lower limit of median class,
n = number of observations,
cf = cumulative frequency of class preceding the median class,
f = frequency of median class,
h = class size (assuming class size to be equal)
For the given class,
l=400
n=44
cf=8
f=20
h=100
Median=400+[22820]×100
=400+(228)×5
=400+70
=470
The median is 470.


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