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Question

Find the median of the given data:

Wages(in Rs.)200−300300−400400−500500−600600−700No.of Labourers3520106


A

300

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B

420

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C

400

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D

470

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Solution

The correct option is D

470


Less than frequency distribution for the data is :
Wages less than Rs.Number of Labourers30034008500286003870044

WagesFrequencyCumulative frequency200300333004005840050020285006001038600700644

In the above distribution the total number of observations (labourers) is 44. Hence n = 44.
n2=22.
The cumulative frequency that is greater than 22 and closest to 22 is 28. The class corresponding to this frequency is 400-500. This is the median class.
Median=l+(n2cff)×h
Where,
l = lower limit of median class,
n = number of observations,
cf = cumulative frequency of class preceding the median class,
f = frequency of median class,
h = class size (assuming class size to be equal)
For the given class,
l = 400
n = 44
cf = 8
f = 20
h = 100
Median=400+[22820]×100
=400+(228)×5
= 400 + 70
= 470
The median is 470.


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