Find the median term of the following cumulative frequency distribution: xfrequencyCumulativefrequency221134233925458135482156930684347843884240
A
49.5
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B
53.5
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C
54
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D
55
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Solution
The correct option is C 54 Here, the sum of frequencies, n = 40, which is even. So, the median terms will be the n2th and the (n2+1)th observations, i.e. the 20th and the 21st observations. Both the 20th and the 21st observations are 54. So, the median term will be 54.