Find the median value from the given table by drawing the curve of the values.

18.5

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16.5

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17.5

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21.5

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Solution

The correct option is C $17.5$
Total cumulative frequency, $n = 35$
Middle value $= \frac{n}{2} = \frac{35}{2}$
Middle value $= 17.5$
So, the median value corresponding to the $17.5$ cumulative frequency is around $47$ .

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Similar questions

Q. Question 6
The class marks of a frequency distribution are given as follows 15, 20, 25….. the class corresponding to the classmark 20 is:

A) 12.5 - 17.5
B) 17.5 - 22.5
C) 18.5 - 21.5
D) 19.5 - 20.5

Q. The class marks of a frequency distribution are 15, 20, 25, 30, .. . The class corresponding to the class marks 20 is
(a) 12.5−17.5
(b) 17.5−22.5
(c) 18.5−21.5
(d) 19.5−20.5

Choose the correct answer in each of the following questions:
The class marks of a frequency distribution are 15, 20, 25, 30, .... The class corresponding to the class mark 20 is
(a) 12.5-17.5
(b) 17.5-22.5
(c) 18.5-21.5
(d) 19.5-20.5

Q. Consider the following frequency distribution:

Class	0-5	6-11	12-17	18-23	24-29
Frequency	13	10	15	8	11

The upper limit of the median class is
(a) 16.5
(b) 18.5
(c) 18
(d) 17.5

Q. A body started with velocity of

10 {ms}^{- 1}

and moving with an acceleration of

1 {ms}^{- 2}

. The distance covered by the body in

7^{t h}

second is

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Find the median value from the given table by drawing the curve of the values.

The correct option is C 17.5Total cumulative frequency, n=35Middle value =n2=352Middle value =17.5So, the median value corresponding to the 17.5 cumulative frequency is around 47.

The correct option is C $17.5$
Total cumulative frequency, $n = 35$
Middle value $= \frac{n}{2} = \frac{35}{2}$
Middle value $= 17.5$
So, the median value corresponding to the $17.5$ cumulative frequency is around $47$ .