Question

Find the mid point of points $x+y=4$ which are at unit distance from the line $4x+3y-10=0$

Answer 1

The mid of the two gives pts will be the point of intersection of the two lines

$4x+3y-10=0$

$-4(x+y-4)=0$

______________

$-y+6=0$

$\Rightarrow y=6$

$\therefore x=4-y=4-6$

$x=-2$

$(-2,6)$