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Question

Find the middle term in the expansion of (xa−ax)21

A
20C10xa,21C10ax
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B
20C9xa,21C10ax
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C
21C10xa,21C10ax
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D
21C9xa,21C10ax
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Solution

The correct option is C 21C10xa,21C10ax
There are 22 terms in the expansion of (xaax)21.
So, the middle terms are T11 and T12
T11=21C10(xa)11(ax)10=21C10(xa)
and
T12=21C11(xa)10(ax)11=21C11(ax)=21C10(ax)

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