Find the middle term in the expansion of (xa−ax)21
A
20C10xa,21C10ax
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
20C9xa,21C10ax
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
21C10xa,−21C10ax
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
21C9xa,21C10ax
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution
The correct option is C21C10xa,−21C10ax There are 22 terms in the expansion of (xa−ax)21. So, the middle terms are T11 and T12 T11=21C10(xa)11(−ax)10=21C10(xa) and T12=21C11(xa)10(−ax)11=−21C11(ax)=−21C10(ax)