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Standard XII

Mathematics

nth Term of A.P

Find the midd...

Question

Find the middle term of an A.P with $23$ terms, given its first term is $11$ and common difference is $3$

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Solution

$a = 11, d = 3$

Number of terms $= 23$

$∴$ Middle term is $(\frac{23 + 1}{2}) = 12^{t h}$ term is the middle term.

We know that $t_{n} = a + (n - 1) d$

$t_{12} = a + 11 d = 11 + 11 \times 3 = 11 + 33 = 44$

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Find the middle term of an A.P with 23 terms, given its first term is 11 and common difference is 3

a=11,d=3Number of terms=23∴ Middle term is (23+12)=12th term is the middle term.We know that tn=a+(n−1)dt12=a+11d=11+11×3=11+33=44

Find the middle term of an A.P with $23$ terms, given its first term is $11$ and common difference is $3$

$a = 11, d = 3$

Number of terms $= 23$

$∴$ Middle term is $(\frac{23 + 1}{2}) = 12^{t h}$ term is the middle term.

We know that $t_{n} = a + (n - 1) d$

$t_{12} = a + 11 d = 11 + 11 \times 3 = 11 + 33 = 44$