Question

Find the middle term of ${(x-\frac{1}{2x})}^{10}$

Answer 1

$S={(x-\frac{1}{2x})}^{10}$

General term of a binomial expansion,$(x+y{)}^n={\sum }_{r=0}^n{}^n{C}_r{x}^r{y}^{n-r}$

Here, $n=10$ so there are 11 terms, middle term is the sixth term,$r=5$

$T_6{=}^{10}{C}_5{x}^5(-1/2x{)}^5={-}^{10}{C}_5{2}^{-5}$.