CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the middle terms in the expansion of (5x7y)7.

Open in App
Solution

Since n is an odd number, the expansion contains two middle terms.
(7+12)th and
(7+32)th terms are the two middle terms in the expansion of (5x7y)7.
T4=T3+1=(1)37C3(5x)73(7y)3=7C3(5x)4(7y)3
T5=T4+1=(1)47C4(5x)74(7y)4=7C4(5x)3(7y)4

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon