Find the midpoint of a line segment of AB = 8 cm , With AB as base construct an isoceles triangle of 2 equal angles having value of $40^{\circ}$ [3 MARKS]

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Solution

Steps : 1 Mark
Construction : 2 Marks

Steps :
1. Using ruler, draw line segment AB of any appropriate length.
2. Draw 2 arcs of radius more than half the length of AB, with A as centre, one above AB and one below AB.
3. With the same radius, similarly draw 2 arcs with B as the centre.
4. Let the point where the 2 arcs above AB meet be P and the point where the 2 arcs below AB meet be Q.
5. Join PQ to obtain the perpendicular bisector. From A measure and draw a line that makes an angle $40^{\circ}$ with respect to AB.
6. Let this line meet PQ at R.
7. Join RB to complete to complete triangle RAB which is the required the isosceles triangle with both equal angles having value $40^{\circ}$

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Find the midpoint of a line segment of AB = 8 cm , With AB as base construct an isoceles triangle of 2 equal angles having value of 40∘ [3 MARKS]

Find the midpoint of a line segment of AB = 8 cm , With AB as base construct an isoceles triangle of 2 equal angles having value of $40^{\circ}$ [3 MARKS]