Find the midpoints between the coordinates $(2, 3)$ and $(1, 0)$

(\frac{1}{2}, \frac{3}{2})

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(\frac{3}{2}, \frac{1}{2})

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(\frac{3}{2}, \frac{4}{2})

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(\frac{3}{2}, \frac{3}{2})

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Solution

The correct option is D $(\frac{3}{2}, \frac{3}{2})$
Midpoint between the coordinates $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ is:
$(\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$
Therefore, the midpoint between the coordinates $(2, 3)$ and $(1, 0)$ is:
$(\frac{2 + 1}{2}, \frac{3 + 0}{2}) = (\frac{3}{2}, \frac{3}{2})$
Therefore, midpoint is $(\frac{3}{2}, \frac{3}{2})$ .

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Find the midpoints between the coordinates (2,3) and (1,0)

The correct option is D (32,32)Midpoint between the coordinates (x1,y1) and (x2,y2) is:(x1+x22,y1+y22)Therefore, the midpoint between the coordinates (2,3) and (1,0) is:(2+12,3+02)=(32,32)Therefore, midpoint is (32,32).

Find the midpoints between the coordinates $(2, 3)$ and $(1, 0)$