Question

find the min and max value of $50-16x+16y+15=0$

Answer 1

We have,

$50-16x+16y+15=0$

$-16x+16y+65=0$

$16x-16y-65=0.......\left(2\right)$

Differentiating this equation with respect to x and we get,

$\begin{align}

$16-16\frac{dy}{dx}-0=0$

$\frac{dy}{dx}=0$

No maximum and minimum value find this function.

Hence this is the answer.