Find the min value of $x^{2} - 9$

3

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- 3

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- 9

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None of these

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Solution

The correct option is C $- 9$
The min value of $f (x)$ is at $f^{'} (x) = 0$

$⟹ 2 x = 0$

$x = 0$

At $x = 0$

$x^{2} - 9 = 0 - 9 = - 9$

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