Find the minimum and maximum wavelengths of sound in water that is in the audible range $(20 - 20000 H z)$ for an average human ear. Speed of sound in water $= 1450 m s^{- 1}$ .

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Solution

a) for minimum wavelength $n$ should be maximum $n = 20 K H z$
$\Rightarrow v = n λ \Rightarrow λ = (\frac{1450}{20 \times 10^{3}}) = 7.25 c m$ .
b) for maximum wavelength $n$ should be minimum
$\Rightarrow v = n λ \Rightarrow λ = v / n \Rightarrow 1450 / 20 = 72.5 m$ .

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Find the minimum and maximum wavelengths of sound in water that is in the audible range (20−20000 Hz) for an average human ear. Speed of sound in water =1450 ms−1.

a) for minimum wavelength n should be maximum n=20 KHz⇒v=nλ⇒λ=(145020×103)=7.25 cm.b) for maximum wavelength n should be minimum ⇒v=nλ⇒λ=v/n⇒1450/20=72.5 m.

Find the minimum and maximum wavelengths of sound in water that is in the audible range $(20 - 20000 H z)$ for an average human ear. Speed of sound in water $= 1450 m s^{- 1}$ .

a) for minimum wavelength $n$ should be maximum $n = 20 K H z$
$\Rightarrow v = n λ \Rightarrow λ = (\frac{1450}{20 \times 10^{3}}) = 7.25 c m$ .
b) for maximum wavelength $n$ should be minimum
$\Rightarrow v = n λ \Rightarrow λ = v / n \Rightarrow 1450 / 20 = 72.5 m$ .