Question

Find the minimum colatitude which can directl receive a signal from a goestationary satellite.

Answer 1

The colatitude is given by $\theta$
$<OAB={90}^{\circ }<ABOAgain<OBC\theta <OAB\therefore \sin \varphi =\frac{6400}{42000}=\frac{16}{106}=\frac{8}{53}\therefore \varphi ={\sin }^{-1}\frac{8}{53}={\sin }^{-1}0.15$