Question

Find the minimum molecular weight of peroxidase anhydrous enzyme if the percentage of Se in peroxidase anhydrous enzyme is 0.5% by weight (at. wt.=78.4)

Answer 1

Let the molecular weight of enzyme = a
Weight of selenium in enzyme
= 0.5% of a
= 0.5a/100
We know that Atomic weight of selenium
= 78.4

So, 78.4 = 0.5a/100
a = 15680 or 1.5680 x 10⁴