The correct option is B 5
To get the minimum number of notes and coins , we take the maximum value denomination available to us
First we count the number of notes of maximum amount, i.e. ₹2000.
2000×1=2000
So, the remaining amount to pay = 3007 - 2000 = ₹1007.
Next we take the number of notes of the next biggest amount smaller than the leftover, i.e. ₹500.
500×2=₹1000
So, the remaining amount to pay = 1007 - 1000 = ₹7
Next, we take 1 note/coin of ₹5.
So, the remaining amount to pay = 7 - 5 = ₹2
Last, we take 1 note/coin of ₹2.
So, total number of notes/coins = 1 + 2 + 1 + 1 = 5.