Find the minimum value of coefficient of friction between the 6kg block and the surface if the system shown does not accelerate.
A
μ=56
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B
μ=23
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C
μ=12
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D
μ=34
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Solution
The correct option is Aμ=56 The given system can be reframed as
Let the coefficient of friction be μ So, from the given figure we can write the force equations for the condition i.e. system has zero acceleration as (a)T=5g (b)T=f=μ×N=μ(6g) Hence, from above two equations we get μ(6g)=5g ⇒μ=56