wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Find the minimum value of coefficient of friction between the 6 kg block and the surface if the system shown does not accelerate.


A
μ=56
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
μ=23
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μ=12
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
μ=34
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A μ=56
The given system can be reframed as

Let the coefficient of friction be μ
So, from the given figure we can write the force equations for the condition i.e. system has zero acceleration as
(a) T=5g
(b) T=f=μ×N=μ(6g)
Hence, from above two equations we get
μ(6g)=5g
μ=56

flag
Suggest Corrections
thumbs-up
3
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon