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Question

Find the minimum value of coefficient of friction between the 6 kg block and the surface if the system shown does not accelerate.


A
μ=56
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B
μ=23
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C
μ=12
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D
μ=34
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Solution

The correct option is A μ=56
The given system can be reframed as

Let the coefficient of friction be μ
So, from the given figure we can write the force equations for the condition i.e. system has zero acceleration as
(a) T=5g
(b) T=f=μ×N=μ(6g)
Hence, from above two equations we get
μ(6g)=5g
μ=56

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