Find the minimum equilibrium- Take g -10 m - s 2-A- 10 kgB- 15 kgC- 20 kgD- 25 kg

The correct option is D 25 kgFrom FBD of point, T_2sin 45^∘ = 100 N T_2cos 45^∘ =T_1 ⇒ T_1=100 N From FBD of block (limiting case) T_1≤ f = μ mg=0.4mg ⇒ m≥25 k ...

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Standard XII

Physics

Limiting Friction

Find the mini...

Question

Find the minimum value of ' $m$ ', for the sytem to be in equilibrium. Take $g = 10 m / s^{2}$ .

10 k g

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15 k g

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20 k g

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25 k g

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Solution

The correct option is D $25 k g$
From FBD of point,
$T_{2} sin 45^{\circ} = 100 N$
$T_{2} cos 45^{\circ} = T_{1}$
$\Rightarrow T_{1} = 100 N$
From FBD of block (limiting case)
$T_{1} \leq f = μ m g = 0.4 m g$
$\Rightarrow m \geq 25 k g$

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Find the minimum value of 'm', for the sytem to be in equilibrium. Take g=10 m/s2.

The correct option is D 25 kgFrom FBD of point, T2sin45∘=100 N T2cos45∘=T1 ⇒T1=100 N From FBD of block (limiting case) T1≤f=μmg=0.4mg ⇒m≥25 kg

Find the minimum value of ' $m$ ', for the sytem to be in equilibrium. Take $g = 10 m / s^{2}$ .

The correct option is D $25 k g$
From FBD of point,
$T_{2} sin 45^{\circ} = 100 N$
$T_{2} cos 45^{\circ} = T_{1}$
$\Rightarrow T_{1} = 100 N$
From FBD of block (limiting case)
$T_{1} \leq f = μ m g = 0.4 m g$
$\Rightarrow m \geq 25 k g$