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Question

Find the minimum value of the function
f(x) = π216 cot1(x) cot1 x.

A
π2
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B
\N
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C
π2
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D
π
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Solution

The correct option is A π2
f(x)=π216 cot1 (x)(πcot1(x)) = cot1 (x)+ π216 cot1 (x) π = (cot1 (x) π4cot1 (x))2+ π2π π2 fmin = π2







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