The correct option is A M23, M32, M13=16,−20,32 C23, C32, C13=−16, 20, 32
Cij=(−1)i+jMijM23=(5648∣∣∣=40−24=16C23=(−M23)=−16M13=(5248∣∣∣=40−8=32C13=(M13)=32M32=(5753∣∣∣=15−35=−20C32=−M32=20Here M and C represents Minor and Cofactor respectively.
option (a) is correct.