Question

Find the missing digit which makes the number $2$_$42$ exactly divisible by $6$?

• A. $1$
• B. $0$
• C. $2$
• D. $5$

Answer 1

The correct option is A $1$

We know the divisibility rule for $6$:
If the number is exactly divisible by both $2$ and $3$, then the given number is also divisible by $6$.
Here, $2+4+2=8$
So if $1$ is added, then $8+1=9$.
Hence, $2,142$ is divisible by $6$, because the last digit is $2$ which is even and the number is multiple of $3$.
Therefore, the missing digit is $1$.

So, option A is correct.