Question

Find the missing digit which makes the number $873$_$4$ exactly divisible by $6$?

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (B)

$2$

We know the divisibility rule for $6$:
If the number is exactly divisible by both $2$ and $3$ then the given number is also divisible by $6$.
Here, $8+7+3+4=22$
So, $2$ is added to $22+2=24$.
Hence, $87324$ is divisible by $6$, because the last digit ends with even no. and the number is multiple of $3$.
So, option B is correct.