Question

Find the missing digits in the following additions.
$BB$
$+6$
$\underset{–}{+AAA}$
$\underset{–}{461}$

Answer 1

Value of $A=4$ and $B=1$
Step-by-step explanation:
Given: $BB+6+AAA=461$
To find: value of $A$ & $B$
$B,6,A$ and $1$ are on unit place
which means $B+6+A=1$
gives $B=1$ & $A=4$ .i.e., $1+6+4=11$
now we check these value for rest of equation,
$BB+6+AAA=11+6+444=461$
Since $B=1$ and $A=4$ satisfy the given equation
Therefore, Value of $A=4$ and $B=1$