Find the missing frequency in the following distribution if N is 60 and median is 40 - array - c - c - c - c - c - c - hline Frequency - 5 -ext F 1-text F 2- 8 - 2lend array

[ Marks amp; Frequency amp; Cumulative frequency; 0 10 amp; 5 amp; 5; ...

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Standard XI

Statistics

Mean Deviation from Median for Discrete Series

Find the miss...

Question

Find the missing frequency in the following distribution if N is 60 and median is 40.
$\begin{matrix} Marks & 0 - 10 & 10 - 30 & 30 - 60 & 60 - 80 & 80 - 90 Frequency & 5 & F1 & F2 & 8 & 2 \end{matrix}$

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Solution

$\begin{matrix} Marks & Frequency & Cumulative frequency 0 - 10 & 5 & 5 10 - 30 & F_{1} & 5 + F_{1} 30 - 60 & F_{2} & 5 + F_{1} + F_{2} 60 - 80 & 8 & 13 + F_{1} + F_{2} 80 - 90 & 2 & 15 + F_{1} + F_{2} N = 60 \end{matrix}$
$∵ N = 60 ∵ 15 + F_{1} + F_{2} = 60 F_{1} + F_{2} = 45 Median Size = \frac{N}{2} = \frac{60}{2} = 30 th item. ∵ M = 40 ∴ Median Class is 30 - 60. M = L_{1} + \frac{\frac{N}{2} - C . f}{f} \times c 40 = 30 + \frac{\frac{60}{2} - (5 + F_{1})}{F_{2}} \times 30 10 = \frac{(25 - F_{1})}{F_{2}} \times 30 10 F_{2} = 750 - 30 F_{1} 30 F_{1} + 10 F_{2} = 750 3 F_{1} + F_{2} = 75.... e q (1) F_{1} + F_{2} = 45...... e q (2) Solving eq (1) and eq (2) 2 F_{1} = 30 F_{1} = 15 F_{2} = 30$

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Find the missing frequency in the following distribution if N is 60 and median is 40. Marks0−1010−3030−6060−8080−90Frequency5F1F282

Find the missing frequency in the following distribution if N is 60 and median is 40.
$\begin{matrix} Marks & 0 - 10 & 10 - 30 & 30 - 60 & 60 - 80 & 80 - 90 Frequency & 5 & F1 & F2 & 8 & 2 \end{matrix}$