By Decoding the given Sequence in the way A→1;B→2;....Z→26
??
PSV→16,19,22
EHK→5,8,11
TWZ→20,23,26
ILO→9,12,15
This problem can be solved by alternate sequence method
The third term has the numbers 5,8,11 and the 5th term has 9,12,15 it means every number has increased by 4 than its preceeding one . So, the numbers of the 1st term will be 1,4,7 i.e ADG