Question

Find the missing number

$\frac{16}{n}=\frac{48}{36}$

Answer 1

Step-1: Write $a,b,candd$as $\frac{16}{n}=\frac{48}{36}$is written in the form of $\frac{a}{b}=\frac{c}{d}$

$a=16$ $b=n$ $c=48$ $d=36$

Step-2: Write mean terms and extreme terms

$meanterms:-$ $b=n$ $c=48$

$extremeterms:-$ $a=16$ $d=36$

Step-3: use $onemean=\frac{productofextremes}{othermean}$ as one mean term is missing

$onemean=\frac{productofextremes}{othermean}$

$n=\frac{48\times 36}{16}$

$n=\frac{1728}{16}$ ( simplify $\frac{1728}{16}$by dividing by a common factor $16$in numerator and denominator separately )

$n=108$

Hence, the missing number is $n=108$