Question

Find the missing term for the sequence:
11, 13, 18, 26, 37, ___, 68

Answer 1

Let's find the difference of each pair of consecutive terms of the given series.

The difference of each pair of consecutive terms form an arithmetic sequence $:2,5,8,11$ with a common difference of $3.$

$\therefore$ The next term of the arithmetic series is $11+3=14.$

Hence, the term after $37$ is $37+14=51$

The sequence is $11,13,18,26,37,51,68.$