Find the missing term
23 : 31 = 41 : _____

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Solution

The correct option is B 47
The given numbers are alternate prime number
23, 29, 31
Two consecutive prime number after 41 are 43 and 47.
41, 43, 47
we have to take alternate prime number ---- 47

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\frac{{(3 \frac{1}{4})}^{4} - {(4 \frac{1}{3})}^{4}}{{(3 \frac{1}{4})}^{2} - {(4 \frac{1}{3})}^{2}} = {(\frac{13 a}{12})}^{2}

a

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