Let the common difference for this AP be d.
Given that the 2nd term in this AP is 3, and the 4th term is -5.
i.e., a2=3 and a4=−5
Since a3=a2+d and a4=a3+d, we have
a4=a3+d=(a2+d)+d=a2+2d.
⟹−5=3+2d
⟹d=−4
a2=a1+d
⟹a1=a2−d=3−(−4)=7
Thus, the 1st term of the AP is 7.
a4=a3+d
⟹a3=a4−d=−5−(−4)=−1
Thus, the 3rd term of the AP is -1.