Question

Find the missing terms such that the given polynomial become a perfect square trinomial :
$81x^2+$__________$+4$

Answer 1

$81x^2+---+4$

$x^2+\frac{1}{81}\times ---+\frac{4}{81}$

$\frac{\lambda }{81}$ be coefficient

of x

To find last term

$(\frac{\frac{\lambda }{81}}{2}{)}^2$ =$\frac{4}{81}$

$(\frac{\lambda }{81\times 2}{)}^2=\frac{4}{81}$

$\frac{{\lambda }^2}{\left(81\right)\left(81\right)\left(4\right)}$ =$\frac{4}{81}$

${\lambda }^2=16\times 81$

${\lambda }^2=1296$

$\lambda =36$

$x^2+\frac{36}{81}x+\frac{4}{81}$

$81x^{2}36x+4$

$(9x+2{)}^2$