Find the missing value in the table given below

Weight of grain (Kg) 4 6 10 20

Cost (Rs) 200 400 800

1500

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1700

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1800

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2000

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Solution

The correct option is C 1800
Obtaining the relation between the weight and cost of a grain we have:
Let, Cost of 20 kg be Rs X.
$\frac{6 - 4}{400 - 200}$ = $\frac{20 - 10}{X - 800}$
$\frac{1}{100} = \frac{10}{X - 800}$
Solving for X,
X= Rs 1800

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Find the missing value in the table given below Weight of grain (Kg) 4 6 10 20 Cost (Rs) 200 400 800

The correct option is C 1800Obtaining the relation between the weight and cost of a grain we have: Let, Cost of 20 kg be Rs X. 6−4400−200= 20−10X−800 1100=10X−800 Solving for X, X= Rs 1800

Find the missing value in the table given below

Weight of grain (Kg) 4 6 10 20

Cost (Rs) 200 400 800

The correct option is C 1800
Obtaining the relation between the weight and cost of a grain we have:
Let, Cost of 20 kg be Rs X.
$\frac{6 - 4}{400 - 200}$ = $\frac{20 - 10}{X - 800}$
$\frac{1}{100} = \frac{10}{X - 800}$
Solving for X,
X= Rs 1800