Find the mode and median of the following frequency distribution table
$\begin{matrix} x & 10 & 11 & 12 & 13 & 14 & 15 f & 1 & 4 & 7 & 5 & 9 & 3 \end{matrix}$

14 , 13

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20 , 21

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13 , 14

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10 , 13

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Solution

The correct option is A
14 , 13

$\begin{matrix} x & f & c . f 10 & 1 & 1 11 & 4 & 5 12 & 7 & 12 13 & 5 & 17 14 & 9 & 26 15 & 3 & 29 T o t a l & N = 29 \end{matrix}$

Mode = 14

Median = $\frac{N + 1}{2}$ = $\frac{29 + 1}{2}$ = 15 th observation

= 13

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Similar questions

Find the mean, mode and median of the following frequency distribution. [CBSE 2010]

Class	0−10	10−20	20−30	30−40	40−50	50−60	60−70
Frequency	4	4	7	10	12	8	5

Q. For a symmetrical frequency distribution, we have:
(a) mean < mode < median
(b) mean > mode > median
(c) mean = mode = median
(d) mode =

\frac{1}{2}

(mean + median)

Find the median for the following frequency distribution table:

Class-intervals	0 - 5	5 -10	10 - 15	15 - 20	20 - 25	25 - 30
Frequency	5	3	9	10	8	5

Find the median for the following frequency distribution table:

Class Intervals	110 - 119	120 - 129	130 - 139	140 - 149	150 - 159	160 - 169
Frequency	6	8	15	10	6	5

Find the mode and median of the following frequency distribution table
$\begin{matrix} x & 10 & 11 & 12 & 13 & 14 & 15 f & 1 & 4 & 7 & 5 & 9 & 3 \end{matrix}$

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Find the mode and median of the following frequency distribution table x101112131415f147593

The correct option is A 14 , 13 xfc.f1011114512712135171492615329TotalN=29 Mode = 14 Median = N+12 = 29+12 = 15 th observation = 13

Find the mode and median of the following frequency distribution table
$\begin{matrix} x & 10 & 11 & 12 & 13 & 14 & 15 f & 1 & 4 & 7 & 5 & 9 & 3 \end{matrix}$

The correct option is A
14 , 13

$\begin{matrix} x & f & c . f 10 & 1 & 1 11 & 4 & 5 12 & 7 & 12 13 & 5 & 17 14 & 9 & 26 15 & 3 & 29 T o t a l & N = 29 \end{matrix}$

Mode = 14

Median = $\frac{N + 1}{2}$ = $\frac{29 + 1}{2}$ = 15 th observation

= 13