Find the mode- beginarray -WhineClass interval - Frequency 100-110 - 8 Wllhline110-120 - 9 -Hhline 120-130 - 11 Whline130-140 - 12 11 hine140-150 - 10 Whline -ndarray -2 MARKS-

Concept: 1 Mark Application: 1 Mark Modal Class is 130 140 Mode =I+ (f_1 f_0/2f_1 f_0 f_2) × h = 130 + 12 11/24 11 10× 10 =133.33 ...

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Standard X

Mathematics

Finding Mode for Ungrouped Data

Find the mode...

Question

Find the mode.

$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y 100 - 110 & 8 110 - 120 & 9 120 - 130 & 11 130 - 140 & 12 140 - 150 & 10 \end{matrix}$ [2 MARKS]

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Solution

Concept: 1 Mark
Application: 1 Mark

Modal Class is 130-140

Mode
$= I + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$

$= 130 + \frac{12 - 11}{24 - 11 - 10} \times 10$

$= 133.33$

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Find the mode. Class intervalFrequency100−1108110−1209120−13011130−14012140−15010 [2 MARKS]

Concept: 1 Mark Application: 1 Mark Modal Class is 130-140 Mode =I+(f1−f02f1−f0−f2)×h =130+12−1124−11−10×10 =133.33

Find the mode.

$\begin{matrix} C l a s s i n t e r v a l & F r e q u e n c y 100 - 110 & 8 110 - 120 & 9 120 - 130 & 11 130 - 140 & 12 140 - 150 & 10 \end{matrix}$ [2 MARKS]

Concept: 1 Mark
Application: 1 Mark

Modal Class is 130-140

Mode
$= I + (\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}}) \times h$

$= 130 + \frac{12 - 11}{24 - 11 - 10} \times 10$

$= 133.33$