Find the mode of the following data- - Classinterval 25-35 35-45 45-55 55-65 65-75 75-85 85-95- Frequency 12 16 17 15 8 19 13- -

Modal Class is 75 85 Mode=I+(f_1 f_0/2f_1 f_0 f_2)×h =75+19 8/38 8 13×10=81.47. ...

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Standard IX

Mathematics

Finding Mode for Grouped Data When Class Intervals Are GivenÂ

Find the mode...

Question

Find the mode of the following data.

$\begin{matrix} C l a s s i n t e r v a l & 25 - 35 & 35 - 45 & 45 - 55 & 55 - 65 & 65 - 75 & 75 - 85 & 85 - 95 F r e q u e n c y & 12 & 16 & 17 & 15 & 8 & 19 & 13 \end{matrix}$

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Solution

Modal Class is 75-85

Mode=I+ $(\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}})$ $\times$ h

=75+ $\frac{19 - 8}{38 - 8 - 13}$ $\times$ 10=81.47.

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Similar questions

Q. Find the median of the following data:

\begin{matrix} Class interval & 25 - 35 & 35 - 45 & 45 - 55 & 55 - 65 & 65 - 75 & 75 - 85 & 85 - 95 Frequency & 12 & 16 & 17 & 15 & 8 & 19 & 13 \end{matrix}

If the mean of the data is 60, find the value of p

$\begin{matrix} C l a s s m a r k & f r e q u e n c y 25 - 35 & 12 35 - 45 & 16 45 - 55 & p 55 - 65 & 15 65 - 75 & 8 75 - 85 & 19 85 - 95 & 13 \end{matrix}$

Q. Compute the mode from the following series:

Size	45-55	55-65	65-75	75-85	85-95	95-105	105-115
Frequency	7	12	17	30	32	6	10

Q. Find out the mode value from the following data:

Mid-value	15	25	35	45	55	65	75	85
Frequency	5	8	12	16	28	15	3	2

Find the mean of the following data, using step-deviation method.

Class	5−15	15−25	25−35	35−45	45−55	55−65	65−75
Frequency	6	10	16	15	24	8	7

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Find the mode of the following data. Class interval25−3535−4545−5555−6565−7575−8585−95Frequency1216171581913

Modal Class is 75-85 Mode=I+(f1−f02f1−f0−f2)×h =75+19−838−8−13×10=81.47.

Find the mode of the following data.

$\begin{matrix} C l a s s i n t e r v a l & 25 - 35 & 35 - 45 & 45 - 55 & 55 - 65 & 65 - 75 & 75 - 85 & 85 - 95 F r e q u e n c y & 12 & 16 & 17 & 15 & 8 & 19 & 13 \end{matrix}$

Modal Class is 75-85

Mode=I+ $(\frac{f_{1} - f_{0}}{2 f_{1} - f_{0} - f_{2}})$ $\times$ h

=75+ $\frac{19 - 8}{38 - 8 - 13}$ $\times$ 10=81.47.